|
Getting the GUI language of Inventor |
Top Previous Next |
|
This works:
MessageBox.Show(m_Inventor.LanguageName + " " + m_Inventor.LanguageCode.ToString());
Here is an example of LanguageName: "English" and LanguageCode: "en-US"
|
Text, images and diagrams © 2021 Owen F. Ransen. All rights reserved. (But copy the source code as much as you want!)